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#26 | ||||||||||||||||||||||||
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Core Member [130%]
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Nope. You forget that the universe is expanding and that most of these electrons would not be traveling anywhere the speed of light, thus for all practical purposes charge is local
Huh? The universe does't have a center therefore analogies to the sphere do not make sense.
No center to the universe prevents you from doing this.
And thus this isn't true.
No. See recombination
Yes
It doesn't exactly work like this. You can't just ignore antiparticle creation because electrons are always created in an electron antielectron pair, with the exception of whatever process breaks matter/antimatter symmetry. Furthermore in many cases those particles created will immediately annihilate, so the process is actually much more complicated. Essentially the question you are interested in is if the process which breaks matter/antimatter symmetry. In particular, in most working theories, lepton and baryon asymmetry are exactly balanced, so there would not be any charge symmetry violations. There is no apriori reason to do this, other then there is no experimental evidence for charge violations during matter/antimatter symmetry breaking, and any charge violation that was not very very very very small would be visible on large scale galaxy map surveys. So it could be done, but there is no experimental or theoretical reason to do so, and the fine tuning required to make it not observable on current observations would be very very precise.
Yeah. Its a bitch :P You can essentially treat the particles in the universe as a gas and then use thermodynamics to give you the information you want. |
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#27 | |||
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Member [19%]
MBTI: INTP
Join Date: Mar 2009
Posts: 761
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They wouldn't necessarily have to annihilate each other, since momentum would be conserved: they would physically be separated. The only reason I neglected antiparticle formation and destruction was that it would conserve charge, regardless. Guess that doesn't really work, because I was reading on the conservation of baryonic matter during some of these processes, so it might not be easier to create an electron if production changes these conservation values. |
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#28 | |||
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Veteran Member [56%]
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The infamous Hawking Radiation defense... |
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#29 | |||
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Core Member [163%]
MBTI: INTP
Join Date: Jan 2008
Posts: 6,530
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The hole may have a charge, it may be the most strongly charged body in the universe, yet it would make no difference. Once the particle has fallen in it is effectively removed from the rest of the universe, thus the black hole provides an infinite sink. |
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#30 | |||
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Core Member [130%]
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Um, how do you figure? Unless you are positing that general relativity is wrong, black holes do have charge. For sufficiently distance objects you can treat them as point charges. |
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