View Full Version : Math shuffle...
Cam66
08-15-2010, 09:04 PM
Rules:
Take the equation from the previous post and yield another valid equation by doing only 2 of the following:
*change a symbol
*add one digit
*remove one digit
*change one digit
Example:
Starting Equation: 1+1+1=3
Correct Changes could include:
1-1+1=1
1x1+2=3
Here we go:
10+20+30=50
OwenF
08-16-2010, 06:15 AM
10 + 20 - 30 = 0
GouldFan
08-16-2010, 06:40 AM
20 + 20 -30 = 10
themuzicman
08-16-2010, 06:49 AM
2 x 20 - 30 = 10
GouldFan
08-16-2010, 06:57 AM
Can we use brackets? Are we using + - ÷ x only?
2 x 20 + 30 = 70
themuzicman
08-16-2010, 08:56 AM
2 x 20 + 3 + 0 < 70
GouldFan
08-16-2010, 10:04 AM
2 + 20 + 3 + 7 < 70
I think we would need to clarify some rules here. :)
Condo
08-17-2010, 02:29 PM
((2 + 20) x 3) + 7 >70
I suppose brackets are fine for simplicity. It'll get difficult to make them work without.
But, ignore the brackets when it comes to making a new one?
2 + 20 x 3 + 8 = 70
I detest inequalities.
GouldFan
08-17-2010, 09:33 PM
I detest inequalities.
I agree. It makes the game too easy.
3 + 20 x 3 + 8 = 71
Condo
08-18-2010, 09:14 AM
3 + 20 x 2 + 8 = 51
themuzicman
08-18-2010, 10:20 AM
3 + 20 / 2 + 8 = 21
masterpeach
08-18-2010, 12:12 PM
3 - 20/2 + 8 = 1
themuzicman
08-18-2010, 12:16 PM
3 - 20/2 + 8 = 0 + 1
masterpeach
08-18-2010, 12:35 PM
3 + 20/2 + 8 = 20 + 1
Condo
08-18-2010, 02:10 PM
3 + 20 / 2 + 8 = 20 + 1 / 1
Lets expand.
GouldFan
08-19-2010, 05:44 AM
3 + 20 / 2 + 7 = 20 + 1 - 1
Changing only 2 seems a little restrictive. :thinking:
themuzicman
08-19-2010, 06:43 AM
3 + 20 / 4 + 7 = 20 + 1 - 6
GouldFan
08-19-2010, 06:50 AM
3 + 20 - 4 + 7 = 20 + 1 x 6
themuzicman
08-19-2010, 06:51 AM
3 + 20 - 4 + 7 = 20 + 1^2 x 6
GouldFan
08-19-2010, 07:00 AM
3 + 20 - 4 + 7 x 1 = 20 + 1^2 x 6
masterpeach
08-19-2010, 09:17 AM
3 + 20 - 4 + 4 x 1 = 20 + 1/2 x 6
Condo
08-19-2010, 10:52 AM
3 + 29 - 4 + 4 x 1 = 20 + 4/2 x 6
GouldFan
08-19-2010, 02:36 PM
3 + 69 - 4 + 4 x 1 = (20 + 4)/2 x 6
Are we counting one set of brackets as a modification, or can we use it whenever needed?
Condo
08-19-2010, 02:40 PM
((3 + 69) - 4 + 4) x 4 = ( 20 + 4 ) x (2 x 6)
3 + 69 - 4 + 4 x 4 = 20 + 4 x 2 x 6
Id say brackets for simplicity. They only really tell you how to split the equation, they are not tools, necessarily. I doubt this game would be interesting if we had brackets as a modification. Things would change too slowly, and you can only look at it limitedly if so.
But, include a "raw" version underneath, will help with subsequent equations.
masterpeach
08-20-2010, 12:47 AM
But
((3 + 69) - 4 + 4) x 4 =! 3 + 69 - 4 + 4 x 4 !
288 =! 84
As the use of brackets is determined in mathematics, I wouldn't want to use them differently in this game.
vBulletin® v3.8.7, Copyright ©2000-2013, vBulletin Solutions, Inc.